Extra points and brainliest anwser if you ! appropriate

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hanz73

13.03.2022

You should already know

$\cos 30^\circ = \dfrac{\sqrt{3}}{2}$

$\sin 30^\circ = \dfrac 1 2$

Trig as taught really mostly uses 30/60/90 triangles and 45/45/90 triangles. Learn how these are derived and memorize them and you'll be well on your way.

But to do the problem,

$\sin 30^\circ = \dfrac{\textrm{opp}}{\textrm{hyp}} = \dfrac{4}{8} = \dfrac 1 2$

$\cos 30^\circ = \dfrac{\textrm{adj}}{\textrm{hyp}} = \dfrac{4\sqrt{3}}{8} = \dfrac{\sqrt{3}}{2}$

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