jacorey77
20.11.2021 •
Mathematics
F(x) = 3(4)× in an exponential function.
thank you <33
Solved
Show answers
More tips
- H Health and Medicine Simple and Effective: How to Get Rid of Cracked Heels...
- L Leisure and Entertainment What to Bring on a Hike? Essential Items to Pack for a Safe and Enjoyable Adventure...
- L Leisure and Entertainment Couchsurfing: A New Way to Travel...
- S Style and Beauty Autotanning: Harmful or Safe?...
- F Food and Cooking 10 Ideas for a Wedding Anniversary Gift...
- H Health and Medicine How to Reduce Sweating in the Heat and Beyond: Say Goodbye to Excessive Sweat...
- F Food and Cooking Do Aphrodisiacs Really Work? Separating Fact from Fiction...
- H Health and Medicine What to Eat to Lose Weight?...
- A Animals and plants How to Teach Your Parrot to Talk?...
- H Health and Medicine How to Improve Your Posture?...
Answers on questions: Mathematics
- M Mathematics Share 36cm in the ratio 2 1can someone please help...
- M Mathematics Solve for x 4(x + 1) = –28...
- M Mathematics Find the size of angle X....
- M Mathematics PICTURE HELPPP Please please please...
- M Mathematics How much less is 5/6 than 1...
- M Mathematics Work out the size of angle x...
- M Mathematics Solve for X 5(x + 8) = -10...
- M Mathematics Helpo me if you know the answers...
- M Mathematics Show that (X+1)(x+3)(x+5)=ax3+bx2+cx+d...
- M Mathematics John is told to pack 260 oranges and 348 apples into smaller bags. In the first 4 bags, he packed 2 oranges and 3 apples each. He then packed the remaining fruits...
Ответ:
f(x)=12x
Step-by-step explanation:
Like and give 5 star rating
Please brainlest
Ответ:
The possible value of X are;
15, 30, 45, 60 etc
Step-by-step explanation:
The parameters given are
Number of chocolates Tanmay had = X
Number of chocolates Tanmay gave to Akash = 1/3 × X
Number of chocolates Tanmay gave to Sharad = 1/5 × X
Whereby 3 and 5 are factors of X, therefore;
3 × 5 = 15 is the lowest single factor of X
The possible values of X starting from the lowest factor are given as follows;
15 × 1 = 15
15 × 2 = 30
15 × 3 = 45
15 × 4 = 60
Hence, the possible value of X are the arithmetic progression a + (n - 1)×d
Where:
a = 15
n = 1, 2, 3, 4, ...
d = 15
Which includes;
15, 30, 45, 60