f x equal 5 x 3 + g x equals x + 1 find f x g5 to 30 x to the third power + g x equals x + 1 finds (f.g)(x) ​

Step-by-step explanation:

In order for the limit to exist in a piecewise function, both the right-side and left-side limits must be equal to each other:

So, if we plug in x=-1 for the left side limit, we get 2cos(πx) = 2cos(π(-1)) = 2cos(-π) = 2(-1) = -2Plugging in x=-1 for the right-side limit, we get 2/cos(πx) = 2/cos(π(-1)) = 2/cos(-π) = 2/(-1) = -2Since both the right-side and left-side limits are equal to each other, we can say that the limit of f(x) as x approaches -1 from the left side is -2, therefore the limit existsSee the attached graph