Mathematics: Factor each. Please help!

Factor each. Please help! - id9527002, 6224968918

Ответ:

kels7618

11.02.2022

Mathematics

1) The factors of x^2-3x+2=0 are $\mathbf{(x-1)(x-2)=0}$

Option C is correct.

3) The factors of x^2+2x-8=0 are $\mathbf{(x-2)(x+4)=0}$

Option B is correct.

Step-by-step explanation:

1) Factor : x^2-3x+2=0

For factoring we need to break the middle term, such that there sum is equal to middle term of expression and product is equal to product of first and last term.

The middle term : -3x

We can break them as (-2x)( -x)

Solving:

$x^2-3x+2=0\\x^2-2x-x+2=0\\x(x-2)-1(x-2)=0\\(x-1)(x-2)=0$

So, factors of x^2-3x+2=0 are $\mathbf{(x-1)(x-2)=0}$

Option C is correct.

3) Factor: x^2+2x-8=0

For factoring we need to break the middle term, such that there sum is equal to middle term of expression and product is equal to product of first and last term.

The middle term : 2x

We can break them as (4x)( -2x)

Solving

$x^2+2x-8=0\\x^2+4x-2x-8=0\\x(x+4)-2(x+4)=0\\(x-2)(x+4)=0$

So, factors of x^2+2x-8=0 are $\mathbf{(x-2)(x+4)=0}$

Option B is correct.

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Ответ:

querline87

21.03.2022

Mathematics

-27

Step-by-step explanation:

Given: f(x)= -x^2+10x-16, g(x)= |11-2x^2|

f(9)= -(9)^2+10(9)-16

= -7

g(-5)= |11-2(-5)^2|

=39

Solve: 2[f(9)]-1/3[g(-5)]

= 2[(-7)] - 1/3[39]

= -27

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Factor each.

Please help!

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