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keshan3000
24.11.2019 •
Mathematics
Factor the expression on the left side of the equation. then solve the equation.
x³ - 2x² - 5x = 0
-5, 0, 3
0, -1 ± √24
0, -1 ± √6
0, 1 ± √6
Solved
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Ответ:
First, take common factor:
x(x^2 - 2x - 5 )= 0
Now use the quadratic formula to find the roots of the trinomial
x = [- b +/- √(b^2 - 4(a)(c)] / 2a
x = [2 +/-2√6 ]/2
x = 1 + √6 and x = 1 -√6
Then the solutions are:
x =0; x = 1 + √6; x = 1 - √6
That is the las option shown.
Ответ:
18month=1.5 year
Interest = 0.06*930*1.5=$83.7