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devalynn
30.06.2019 •
Mathematics
Factor the following expression completely given that one of the factors is (w − 7): w^3 − 12w^2 + 29w + 42 =
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Ответ:
The factors of w^3 − 12w^2 + 29w + 42 are (w -7), (w-6) and (W + 1 )
Step-by-step explanation:
It is given that (w − 7) is one factor of w^3 − 12w^2 + 29w + 42
When we divide w^3 − 12w^2 + 29w + 42 by w-7 we get the quotient W^2 – 5w -6 and remainder 0
Therefore
w^3 − 12w^2 + 29w + 42 can be written as,
w^3 − 12w^2 + 29w + 42 = (w -7)(W^2 – 5w -6 )
When we factorize W^2 – 5w -6 we get
W^2 – 5w -6 = (w+1)(w-6)
Therefore,
The factors of w^3 − 12w^2 + 29w + 42 are (w -7), (w-6) and (W + 1 )
The long division method is attached with this answer
Ответ: