farihasy6508
24.07.2020 •
Mathematics
Factorise (1) and 2 9
Solved
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Ответ:
666
Step-by-step explanation:
666 666 666 666 666 666 666 666 666 666 666 666 6666 666 666 666 666 666 666 666 66 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 6666 666 666 666 666 666 666 666 66 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 6666 666 666 666 666 666 666 666 66 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 6666 666 666 666 666 666 666 666 666 666 666 666 666 666 6666 666 666 666 666 666 666 666 66 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 6666 666 666 666 666 666 666 666 6666 666 666 666 666 666 666 666 66 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 6666 666 666 666 666 666 666 666 66 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 6666 666 666 666 666 666 666 666 66 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666 666
Ответ:
There is difference in the scores of males and females
Step-by-step explanation:
Given that a professor teaches a certain section of material using a lot of examples with sports and cars to illustrate. He is concerned that this may have biased his instruction to favor male students
Since simple variances are unequal, we can do t test for comparison of two means with unequal variances
Group Group One Group Two
Mean84.0078.00
SD4.008.00
SEM1.262.53
N10 10
The mean of Group One minus Group Two equals 6.00
95% confidence interval of this difference: From 0.06 to 11.94
t = 2.1213
df = 18
standard error of difference = 2.828
The two-tailed P value equals 0.0480
Since p <0.05 we reject null hypothesis
There is difference in the scores of males and females