Find a cubic polynomial with integer coefficients that has $\sqrt[3]{2} + \sqrt[3]{4}$ as a root.

Find the powers

$a^{2}=5+2 \sqrt{6}$

$a^{3}=11 \sqrt{2}+9 \sqrt{3}$

The cubic term gives us a clue, we can use a linear combination to eliminate the root 3 term $a^{3}-9 a=2 \sqrt{2}$ Square $\left(a^{3}-9 a\right)^{2}=8$ which gives one solution. Expand we have $a^{6}-18 a^{4}-81 a^{2}=8$ Hence the polynomial $x^{6}-18 x^{4}-81 x^{2}-8$ will have a as a solution.

Note this is not the simplest solution as $x^{6}-18 x^{4}-81 x^{2}-8=\left(x^{2}-8\right)\left(x^{4}-10 x^{2}+1\right)$

so fits with the other answers.

Khalid and Sue's Height together is 126 Inches. The difference is 6 inches, so therefore you subtract 6 from the total getting you 120 Inches. You do this with all of the problems for example: The first one. Sue is 72 inches and Khalid is 54. Add them together and subtract them by 6 to get your final answer. Please DO NOT quote me on this lol. This is how I read the question. I think this is right but I am not absolutely 100% sure. Hope this helps.