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frankierice020
09.07.2019 •
Mathematics
Find a positive number that equals 42 when added to it's square
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Ответ:
if the number is x, then
the positive number, when added to its square (remember, its=posessive and it's is a constraction), equals 42
this can be writen as![x+x^2=42](/tpl/images/0071/1834/53b76.png)
perfect, we need to solve by making one side 0 and then factoring since if ab=0, we can assume and solve for a and b by saying that a=0 and b=0
minus 42 from both sides
now, either use the quadratic formula or complete the square or factor
I will factor
find what 2 numbers multiply to get -42 and add to get 1 (since the linear coefient is 1 and the constant is -42)
those numbers are -6 and 7
factor
set each to 0
x-6=0
x=6
x+7=0
x=-7, false since we wanted a positive number
the number is 6
Ответ:
nPr = (n!)/((n-r)!)
20P15 = (20!)/((20-15)!)
20P15 = (20!)/(5!)
The final answer is choice A