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hernandezaniyah660
22.07.2019 •
Mathematics
Find all critical points of the given plane autonomous system. (enter your answers as a comma-separated list.) x' = x + xy y' = −y − xy
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Ответ:
There are 4 critical points: (0, 0), (0, -1), (-1, 0), and (-1, -1).
Ответ:
Hello!
6 girls and 2 boys are to be seated in a row, with 4 girls seated btwn the 2 boys.
Now let us number 8 seats, starting from the left as follows:
S1, S2, S3, S4, S5, S6, S7, S8
Now the following cases arise regarding the seating arrangement of the boys -
B1 seated on S1 and B2 seated on S6 ( leaving S 2,3,4 & 5)
Now in the remaining 6 seats, 6 girls can be arranged in 6! ways = 720 ways.
On interchanging B1 and B2′s place, we get 720 more arrangement
Therefore, current total = 1440 ways
2. B1 - S2 and B2 - S7
1440 more arrangements can be formed as in previous case.
3. B1 - S3 and B2 - S8
1440 more arrangements can be formed as in previous case.
Therefore total ways to arrange the seating plan are 1440 × 3 = 4320 ways
Hope This helped you! :D