Find all of the zeros of f(x) = 5x^2 +40x-100
(multiple choice is up above) if it’s right i promise to mark brainles!

B

Step-by-step explanation:

Given

5x² + 40x - 100

To find the zeros equate to zero, that is

5x² + 40x - 100 = 0 ( divide all terms by 5 )

x² + 8x - 20 = 0

To factor the quadratic

Consider the factors of the constant term (- 20) which sum to give the coefficient of the x- term (+ 8)

The factors are + 10 and - 2, since

10 × - 2 = - 20 and 10 - 2 = + 8, thus

(x + 10)(x - 2) = 0

Equate each factor to zero and solve for x

x + 10 = 0 ⇒ x = - 10

x - 2 = 0 ⇒ x = 2

Zeros are x = - 10 and x = 2 → B

You just have to devide them for ex. 2/7 = 2 devised by 7 is  0.29

4/5= 0.8

7/20= 0.35

1/25=0.04

9/30=0.3

18/24=0.75

5/8=0.6

2/3=0.7

1/9=0.1

8/14= 0.57

And that’s it I hope it helped!!❤️