Mathematics: Find an equation for the contour of f(x,y)=2x2y+7x+20f(x,y)=2x2y+7x+20 that goes through the point (3,−2)(3,−2).

Find an equation for the contour of f(x,y)=2x2y+7x+20f(x,y)=2x2y+7x+20

Ответ:

charleetrill8304

15.03.2022

Mathematics

A contour at height c have $\mathbf{f(x, y) = c}$ as its equation

The equation of the contour is $\mathbf{2x^2y + 7x + 15 = 0}$

The given parameters are:

$\mathbf{f(x,y) = 2x^2y + 7x + 20}$

$\mathbf{(x,y) = (3,-2)}$

Recall that:

$\mathbf{f(x, y) = c}$

Substitute $\mathbf{(x,y) = (3,-2)}$ in f(x,y)

$\mathbf{f(x,y) = 2x^2y + 7x + 20}$

$\mathbf{f(3,-2) = 2 \times 3^2 \times -2 + 7 \times 3 + 20}$

Evaluate exponents

$\mathbf{f(3,-2) = 2 \times 9 \times -2 + 7 \times 3 + 20}$

Evaluate the products

$\mathbf{f(3,-2) = -36 + 21 + 20}$

$\mathbf{f(3,-2) = 5}$

Replace 3 and -2, with x and y

$\mathbf{f(x,y) = 5}$

Substitute 5 for f(x,y) in $\mathbf{f(x,y) = 2x^2y + 7x + 20}$

$\mathbf{2x^2y + 7x + 20 = 5}$

Collect like terms

$\mathbf{2x^2y + 7x + 20 - 5 = 0}$

$\mathbf{2x^2y + 7x + 15 = 0}$

Hence, the equation of contour is $\mathbf{2x^2y + 7x + 15 = 0}$

Read more about equations of parabola at:

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Find an equation for the contour of f(x,y)=2x2y+7x+20f(x,y)=2x2y+7x+20 that goes through the point (

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Ответ:

yasyyas646646

15.03.2022

Mathematics

That equation will be
.. f(x, y) = f(3, -2)
.. 2x^2y +7x +20 = 2*3^2*(-2) +7*3 +20

2x^2*y +7x +20 = 5

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Ответ:

carlshiabrown

16.03.2021

Mathematics

18.6inches

Step-by-step explanation:

Given the length of a side of a pentagon to be 6 inches.

If this length is dilated by a factor of 3.1, the new length will be;

New length = Old length * dilation factor

New length = 6 * 3.1

New length = 18.6inches

Hence the length of each side of the dilated pentagon is 18.6inches

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Find an equation for the contour of f(x,y)=2x2y+7x+20f(x,y)=2x2y+7x+20 that goes through the point (3,−2)(3,−2).

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