samueltaye
21.09.2019 •
Mathematics
Find an equation for the nth term of the arithmetic sequence.
a19 = -92, a20 = 6
a. an = -1856 + 98(n - 1)
b. an = -1856 - 98(n - 1)
c. an = -1856 - 98(n + 1)
d. an = -1856 + 98(n + 1)
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Ответ:
d = 92+6 = 98
an = a1 + 98 (n-1)
a1=a19-98 (n-1)
a1=-92 -98 * 18
=-1856
It’s A ( an = -1856+98(n-1) )
Ответ:
answer b
Step-by-step explanation:
cuz da guy above said so and he looks cool so here I reach