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mlandon922
04.02.2020 •
Mathematics
Find an equation of the line parallel to x=5y-9 and passing through (2,-4). express in standard form.
me .
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Ответ:
x - 5y = 22
Step-by-step explanation:
Step 1: rewrite the equation of the given line in to slope-intercept form by solving for y
x = 5y - 9
-5y = -x - 9 (subtract 5y and x from both sides)
y = x/5 + 9/5 (divide both side by -5)
Step 2: Our line is parallel to this line, so it has the same slope, but a different y-intercept, so set up the equation...
y = x/5 + b
We are given a point (x, y) of (2, -4), so plug that in and solve for b.
-4 = 2/5 + b
-4 - 2/5 = b (subtract 2/5 from both sides to isolate b)
-20/5 - 2/5 = b
-22/5 = b (simplify)
So the equation of our line is y = x/5 - 22/5
Step 3: Standard form is ax + by = c, where a is a positive integer
subtract x/5 from both sides...
-x/5 + y = - 22/5
multiply by -5 so x becomes a positive integer
x - 5y = 22
Ответ:
HUH
Step-by-step explanation: