alexisozl9253
27.09.2021 •
Mathematics
Find an equation of the line that is perpendicular to 10 x + 11 y = 10 and passes through ( − 4 , 8 )
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Ответ:
y = (11/10)x + 62/5
Step-by-step explanation:
First find the slope of the given line 10 x + 11 y = 10. To do this, solve this equation for y and take the slope of the line from the result:
11y = 10 - 10x, or y = (-10/11)x + C, where C is just a constant. The slope of the given line is (-10/11).
The slope of any line perpendicular to the one above has a slope which is the negative reciprocal of the slope of the given line:
The negative reciprocal of (-10/11) is (11/10).
Starting with the slope-intercept form y = mx + b, and substituting the knowns, we are able to find the value of b:
y = mx + b => 8 = (11/10)(-4) + b, or
8 = -44/10 + b, or
80 = -44 + 10b
Then 10 b = 124, and so b = 62/5
The desired equation is thus y = (11/10)x + 62/5
Ответ:
330
Step-by-step explanation:
Given there are 11 books to be selected, and a final 7 has been selected. To find the number of possible ways, we calculate the selection combination;
Hence, the books can be selected in 330 different ways.