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fendyli2353
01.07.2019 •
Mathematics
Find an equation of the line that satisfies the given conditions. through (â1, â2); perpendicular to the line 2x + 5y + 3 = 0
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Ответ:
x = 21
x= -25
Step-by-step explanation:x^2+4-525=0
x^21x+25x-525=0
x{_x^2__ - __3.7__) +5^2 (_5^2.x___ - _3.5^2.7)
x x 5^2 5^2
x(x^2-1-(3.7))+5^2(x-(3.7))=0
x(x-27)+5^2(x-21)=0
(x-21)((x(_x-21_) + _5^2(x-21)_)=0
x-21 x-21
(x-21)(x+5^2)=0
(x-21)(x+25)=0
x- 21 =0
x+25= 0
x-21+21=21
(x+25)-25=-25
x=21
x+25-25=-25
x= 21
x= -25