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08.10.2021 •
Mathematics
Find an equation of the straight line that is perpendicular to the straight line x+2y=5 and that passes through the point (3,7)
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Ответ:
y = 2x + 1
Step-by-step explanation:
Rewrite the equation in standard form:
x+2y=5
2y = -x + 5
y = -(1/2)x + (5/2)
A line perpendicular to this would have a slope that is the negative inverse of the reference line slope, -(1/2), here. The new slope would be 2. The y-intercept, (5/2), will change, so we'll just use b for the new y-intercept, and calculate it later:
y = 2x +b
We know that point (3,7) lies on the new line (it is a solution to the equation), so we can use this point to find the new y-intercept, b.
7 = 2*3 + b
b = 1
The perpendicular line is y = 2x + 1, and goes through point (3,7)
Ответ:
2x-7=23-3x
or, 2x+3x=23+7
or, 5x = 30
or, x = 30/5
or, x = 6
The answer is 6