Mathematics: Find an nth degree polynomial function with real coefficients satisfying the given conditions. degree of the polynomial is 3; the zeros of the polynomial are 3 and i; and use f(2) = 25 to find an

Find an nth degree polynomial function with real coefficients

Ответ:

ochoanene822

02.03.2022

Mathematics

Step-by-step explanation:

Our roots are 3, and i so our roots form

will be

(x - 3)(x - i)

Since i is one root, it conjugate, must be the other.

so we have

(x - 3)(x - i)(x + i)

Simplify

$( {x}^{2} + 1)(x - 3)$

${x}^{3} - 3 {x}^{2} + x - 3$

So the function is

$x {}^{3} - 3 {x}^{2} + x - 3$

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Ответ:

caplode7497

12.10.2021

Mathematics

3)

$\bf slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ f(x_2)}}-{{ f(x_1)}}}{{{ x_2}}-{{ x_1}}}\impliedby 
\begin{array}{llll}
average\ rate\\
of\ change
\end{array}\\\\
-------------------------------\\\\
%x2-4x; -2 ≤x≤ 4 
f(x)=x^2-4x \qquad 
\begin{cases}
x_1=-2\\
x_2=4
\end{cases}\implies \cfrac{f(4)-f(-2)}{4-(-2)}
\\\\\\
\cfrac{[4^2-4(4)]~~-~~[(-2)^2-4(-2)]}{4+2}\implies \cfrac{[16-16]~~-~~[4+8]}{6}
\\\\\\
\cfrac{0-12}{6}\implies \cfrac{-12}{6}\implies \cfrac{-2}{1}\implies -2$

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Find an nth degree polynomial function with real coefficients satisfying the given conditions. degree of the polynomial is 3; the zeros of the polynomial are 3 and i; and use f(2) = 25 to find an

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