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heysonic91

heysonic91

03.06.2021 •

Mathematics

Find cos(A+B), given sinA=35 and cosB=−12/13 and both A and B are in π2<θ<π

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Ответ:

bigboy43

03.07.2021

$\cos(A + B) = \cos A \cos B - \sin A \sin \: B \\ but : \cos \: A = \sqrt{1 - ({ \frac{3}{5} })^{2} } = \frac{4}{5} \\ : \sin B = \sqrt{1 - {( \frac{ - 12}{13} })^{2} } = \frac{5}{13} \\ \therefore \cos(A + B) = ( \frac{4}{5} )( \frac{ - 21}{13} ) - ( \frac{3}{5} )( \frac{5}{13} ) \\ = \frac{ - 84}{65} - \frac{3}{13} \\ = \frac{ - 99}{65} \\ = - 1.52$

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Ответ:

jordanrini

06.06.2022

$\frac{191}{60} kg$ o 3.18 kg

Step-by-step explanation:

1. ENCUENTRA UN DENOMINADOR COMUN

Los denominadores que nos dan son: 4, 2, 5, y 3

Encuentra un numero que es comun cuando multiplicas, seria 60.

2. MULTIPLICA EL NOMINADOR POR LO QUE MULTIPLICASTE EL DOMINADOR

Carne= $\frac{7}{4} kg=\frac{105}{60} kg$

Arroz= $\frac{1}{2} kg=\frac{30}{60} kg$

Fruta= $\frac{3}{5} kg=\frac{36}{60} kg$

Papa= $\frac{1}{3} kg= \frac{20}{60} kg$

3. SUMA LAS FRACIONES

Ahora que tienen el mismo denominador, puedes sumar las fraciones

$\frac{105}{60} kg+\frac{30}{60} kg+\frac{36}{60} kg+\frac{20}{60} kg= \frac{191}{60} kg$ o 3.18 kg

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