Find f (77)
f(p)=7/11p-10:
A: f(77)=59
B: f(77)=39
C: f(77)=49
D: f(77)=67

I don't know, the way it is typed confuses me. Is it 7/11 TIMES p-10 or is p-10 with the 11 as the denominator?  but I do hope this helps:

Step-by-step explanation:

So first I subtracted 7/11 from each side:

f(p)-7/11=(7/11-7/11)p-10

Now we are left with f(4/11p)=p-10

Now to get the variable "p" on one side, I subtracted 4/11p from both sides:

f(4/11p-4/11p)=(p-4/11p)-10

Now we are left with f=7/11p-10

Now we want the "p" to be 1p so we multiply each side by the reciprocal of 7/11:

f(11/7)=(7/11*11/7)p-10

Now we have 1 4/7f=p-10

Now we subtract 4/7 from each side and get:

f=p-9 3/7

And that's as far as I could simplify it, sorry if it's wrong... lol

C. -6a³b^5c^5

Step-by-step explanation:

(3a²bc³) (-2ab^4c²)

= (3a² × (-2a)) (b × b^4) (c³ × c²)

= -6a³ b^5 c^5

Hope it helpful and useful :)