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Jimm6500
25.09.2020 •
Mathematics
Find k so that kx^2 - 12x + 9 is the square of a binomial
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Ответ:
k = 4
Step-by-step explanation:
Given polynomial is,
kx² - 12x + 9
We have to find the value of 'k' for which the given polynomial is a square of a binomial.
To find this we will use the formula,
(a - b)² = a² - 2ab + b²
kx² - 12x + 9 = kx² - 2(6x) + 3²
= kx² - 2(3)(2x) + 3²
By comparing this with the formula of (a - b)²,
b = 3
a = 2x
(2x)²- 2(2x)(3) + 3² = (2x - 3)²
4x² - 12x + 9 = (2x - 3)²
Therefore, k = 4 will make the polynomial a perfect square of a binomial.
Ответ:
$7.97
Step-by-step explanation:
13/10* 1.25+ 27/10*2.35
= 7.97
if my answer helps please mark as brianliest