Find sin(2x), cos(2x), and tan(2x) from the given information. sec(x) = 8, x in Quadrant IV

sin(2x) = 3

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cos(2x) =

tan(2x) =

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If x terminates in the fourth quadrant, then we know that sin(x) < 0 and cos(x) > 0. Given that sec(x) = 8, we immediately have

cos(x) = 1/sec(x) = 1/8

Recall the Pythagorean identity,

cos²(x) + sin²(x) = 1

Then it follows that

sin(x) = -√(1 - cos²(x)) = -3√7/8

Now recall the double angle identities,

sin(2x) = 2 sin(x) cos(x)

cos(2x) = cos²(x) - sin²(x)

Then

sin(2x) = 2 (-3√7/8) (1/8) = -6√7/64 = -3√7/32

cos(2x) = (1/8)² - (-3√7/8)² = -62/64 = -31/32

By definition of tangent,

tan(x) = sin(x)/cos(x)

Then

tan(2x) = sin(2x)/cos(2x) = (=3√7/32) / (-31/32) = 3√7/31

[(5*9)/3]-(1+9)=5

first you would to five times nine and one plus nine:

(45)/3-(10)

then divide 45 by three.

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doing so would give you five as an answer.