ehthaboe7265
14.12.2019 •
Mathematics
Find the 13th term of the sequence 8, -16, 32, -64,
a. 32768
b. -16384
c. -65536
d. none of these
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Ответ:
a(n)=ar^(n-1), a=initial term, r=common ratio, n=term number.
The common ratio,r, is -16/8=32/-16=-64/32=-2, and the first term, a, is 8
So the rule for this sequence is:
a(n)=8(-2)^(n-1), so the 13th term is:
a(13)=8(-2^12)
a(13)=32768
Ответ:
the answer is u are gay
Step-by-step explanation: