Find the 16 term in sequence a(n) = -6+3(n-1)

16th term in sequence a(n) = -6+ (n-1) 3 is 39.

Solution:

Need to determine 16 terms in sequence.

a(n) = -6+3(n-1) that is = -6+ (n-1) 3

from given expression we can say that first term = -6 and common difference d = 3

And given expression = -6+ (n-1) 3 represents formula of nth term of an Arithmetic Sequence.  

So substituting n = 16 in given formula we get  

= -6+ (16-1) 3

=> = -6 + (15 x 3)  

=> = -6 + 45  

=> = 39

Hence 16th term in sequence = -6+ (n-1) 3 is 39.

(You don't need to use pi to find the perimeter of the parallelogram STUV)

12*2 + 8*2 = 24 + 16 = 40