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Thnut236
10.07.2019 •
Mathematics
Find the angle between the diagonal of a cube of side length 9 and the diagonal of one of its faces, so that the two diagonals have a common vertex. the angle should be measured in radians. (hint: we may assume that the cube is in the first octant, the origin is one of its vertices, and both diagonals start at the origin.)
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Ответ:
Firstly, we can sketch points as
O as (0,0,0)
B as (9,0,9)
E as (9,9,9)
now, we can find vectors
OB=(9,0,9)-(0,0,0)
OB=(9,0,9)
OE=(9,9,9,)-(0,0,0)
OE=(9,9,9)
we can use dot product formula to find angle
now, we can find values
now, we can plug these values
now, we can solve for theta
Ответ:
-8.2 divided by 4.1 equals -2
Step-by-step explanation:
x = -8.2