vanna7353
29.02.2020 •
Mathematics
Find the appropriate rejection regions for the large-sample test statistic z in these cases. (Round your answers to two decimal places. If the test is one-tailed, enter NONE for the unused region.)(a) A right-tailed test with α=0.01z >z <(b) A two-tailed test at the 5% significance levelz > _z < _
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Ответ:
a) We have that the significance is given by and we know that we have a right tailed test.
So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:
"=NORM.INV(1-0.01,0,1)"
And we got for this case
So then the rejection region would be
b) We have that the significance is given by , and we know that we have a two tailed test.
So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:
"=NORM.INV(1-0.025,0,1)"
And we got for this case
So then the rejection region would be
Step-by-step explanation:
Part a
We have that the significance is given by and we know that we have a right tailed test.
So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:
"=NORM.INV(1-0.01,0,1)"
And we got for this case
So then the rejection region would be
Part b
We have that the significance is given by , and we know that we have a two tailed test.
So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:
"=NORM.INV(1-0.025,0,1)"
And we got for this case
So then the rejection region would be
Ответ:
slope = rise/ run = 1 /5 for the first choice.
You are right