Mathematics: Find the area and perimeter of the following rectangle. the lengths are 4x+y+2; and 3x+3y. the widths are 2x+y+1 and 12

Find the area and perimeter of the following rectangle.

faithy22

12.03.2022

Equating the lengths, we have: $4x+y+2=3x+3y\Rightarrow x-2y=-2$

Equating the widths, we have: $2x+y+1=12\Rightarrow2x+y=11$

Solving the two equations simultaneously gives that x = 4 and y = 3.

Thus, the length is 4(4) + 3 + 2 = 21 and the width is 12.

Therefore area = length times width = 21 x 12 = 252 square units

perimeter = 2(length + width) = 2(21 + 12) = 2(33) = 66.

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edjiejwi

24.03.2021

i.dk

Step-by-step explanation:

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