LilFlamingo247
14.05.2021 •
Mathematics
Find the Area of the figure below, composed of an isosceles trapezoid and one
semicircle. Rounded to the nearest tenths place
10
Solved
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Ответ:
Area of given figure = 48.28 unit² (Approx.)
Step-by-step explanation:
Given:
Length of parallel lines are 10 , 4 respectively
Diameter of semi-circle = 4
Height of parallelogram = 6
Find:
Area of given figure
Computation:
Radius of semi-circle = Diameter of semi-circle / 2
Radius of semi-circle = 4 / 2
Radius of semi-circle = 2
Area of given figure = [1/2][Sum of parallel line][Height] + [πr² / 2]
Area of given figure = [1/2][10 + 4][6] + [(3.14)(2)² / 2]
Area of given figure = [1/2][14][6] + [(3.14)(4)/ 2]
Area of given figure = 42 + 6.28
Area of given figure = 48.28 unit² (Approx.)
Ответ: