Find the area of the shaded region under the standard normal curve. If convenient, use technology to find the area. z -2.13 0 A normal curve is over a horizontal z-axis and is centered at 0. Vertical line segments extend from the horizontal axis to the curve at negative 2.13 and 0. The area under the curve between negative 2.13 and 0 is shaded. The area of the shaded region is nothing.(Round to four decimal places as needed.)

Using the normal distribution, it is found that the area of the shaded region is of 0.4833.

In a normal distribution, our test statistic is the z-score, which measures how many standard deviations a measure is from the mean. Each z-score has an associated p-value,  which is given at the z-table, and represents the percentile of a measure or or the z-score, which is the area to the left under the normal curve.The area between two z-scores is the subtraction of their p-values.

In this problem, we want the area between Z = -2.13 and Z = 0.

Z = 0 has a p-value of 0.5.Z = -2.13 has a p-value of 0.0166.

0.5 - 0.0166 = 0.4833

The area of the shaded region is of 0.4833.

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The area of the shaded region under the standard normal curve is 0.4834.

Step-by-step explanation:

A random variable X is said to have a normal distribution with mean, µ and variance σ².

Then , is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z N (0, 1).

The distribution of these z-variates is known as the standard normal distribution.

Compute the area under the curve between -2.13 and 0 as follows:

                           

Thus, the area of the shaded region under the standard normal curve is 0.4834.

Is this the whole equation?

Step-by-step explanation:

Cuz if not we need the whole question