cupcakesmc619
03.11.2020 •
Mathematics
Find the center and the radius of the circle x2 + y2 + 6x − 4y − 23 = 0.
Center: (−3, −2), radius: 6
Center: (−3, 2), radius: square root of six end square root
Center: (−3, 2), radius: 6
Center: (3, 2), radius: square root of six end square root
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Ответ:
C
Step-by-step explanation:
It can be written as,
(x+3)^2 +(y-2)^2-23-9-4=0
➡️ (x+3)^2 +(y-2)^2=36
➡️ (x+3)^2 +(y-2) ^2=6^2
Thus,
Centre =(-3,2)
Radius =6 units
Ответ: