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kaitlan225
06.04.2020 •
Mathematics
Find the dimensions of a rectangle whose perimeter is 46m and whose are is 126m^2. Let the width be w. Use the perimeter to find the length in terms of w.
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Ответ:
9 and 14
Step-by-step explanation:
We know that the perimeter is equal to:
P = 2l + 2w = 46
If we divide by 2, we are left with:
l + w = 23
I = 23 - w
Now the area is equal to:
A = l * w = 126
l * w = 126
Now replacing it, we are left with:
(23 - w) * (w) = 126
(-w ^ 2) + 23 * w = 126
Rearranging:
w ^ 2 + -23 * w + 126 = 0
We factor and we have:
(w - 9) * (w - 14) = 0
w - 9 = 0 => w = 9
w - 14 = 0 => 2 = 14
If w = 9, l = 23 - 9 = 14
If w = 14, l = 23-14 = 9
So the dimensions are 9 and 14.
Ответ:
1 meter is equals to> 1000 mm
so
627.532 m> is 627.532*1000> 627532 mm
the answer is
627532 mm