Mathematics: Find the distance from the point (1,2) to the line y=2x-1

X + (x + 1) + (x - 1) = 3003x = 300x = 100The middle number is 100...

Find the distance from the point (1,2) to the

Kelbee781

11.01.2022

distance $= \frac{\bf 1}{\sqrt{\bf 5}}$ units

Step-by-step explanation:

distance $= \frac{|ax_0+by_0+c|}{\sqrt{a^2+b^2}}$

Given equation is y=2x-1

it can be written as 2x-y-1=0

here a=2, y=-1, c=-1 and the point (x_0, y_0) is (1, 2)

distance $= \frac{|2(1)+(-1)(2)-1|}{\sqrt{2^2+1^2}}$

distance $= \frac{|2-2-1|}{\sqrt{4+1}}$

distance $= \frac{|-1|}{\sqrt{5}}$

distance $= \frac{1}{\sqrt{5}}$ units

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