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ayoismeisalex
17.10.2019 •
Mathematics
Find the eighth term of the sequence 2, 1, -2, -7 -14,
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Ответ:
2-1=1-3=-2-5=-7-7=-14
-1
-3
-5
-7
the sequence is +-2
-9
-11
-13
-15
...-14-9=-23
-23-11=-34
-34-13=-47
-47-15=-62
The eighth term of the sequence 2, 1, -2, -7 -14, ... is -47.
Ответ:
(a) Probability that a single randomly selected element X of the population is between 57,000 and 58,000 = 0.46411
(b) Probability that the mean of a sample of size 100 drawn from this population is between 57,000 and 58,000 = 0.99621
Step-by-step explanation:
We are given that a normally distributed population has mean 57,800 and standard deviation 75, i.e.;
= 57,800 and
= 750.
Let X = randomly selected element of the population
The z probability is given by;
Z =
~ N(0,1)
(a) So, P(57,000 <= X <= 58,000) = P(X <= 58,000) - P(X < 57,000)
P(X <= 58,000) = P(
<=
) = P(Z <= 0.27) = 0.60642
P(X < 57000) = P(
<
) = P(Z < -1.07) = 1 - P(Z <= 1.07)
= 1 - 0.85769 = 0.14231
Therefore, P(31 < X < 40) = 0.60642 - 0.14231 = 0.46411 .
(b) Now, we are given sample of size, n = 100
So, Mean of X, X bar = 57,800 same as before
But standard deviation of X, s =
=
= 75
The z probability is given by;
Z =
~ N(0,1)
Now, probability that the mean of a sample of size 100 drawn from this population is between 57,000 and 58,000 = P(57,000 < X bar < 58,000)
P(57,000 <= X bar <= 58,000) = P(X bar <= 58,000) - P(X bar < 57,000)
P(X bar <= 58,000) = P(
<=
) = P(Z <= 2.67) = 0.99621
P(X < 57000) = P(
<
) = P(Z < -10.67) = P(Z > 10.67)
This probability is that much small that it is very close to 0
Therefore, P(57,000 < X bar < 58,000) = 0.99621 - 0 = 0.99621 .