leakcamille8953
17.08.2021 •
Mathematics
Find the equation of a line perpendicular to 5x-4y=-3 that contains the point (5,3)
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Ответ:
Step-by-step explanation:
Equation of given line:
5x-4y=-3
4y=5x+3
y=5/4 x+3
given slope=5/4
Lines are perpendicular so :
required slope=-4/5
By using point slope form:
y-3=-4/5(x-5)
5y-15=-4x+20
5y=-4x+20+15
5y= -4x+35
y=-4/5x+7
Note:if you need to ask any question please let me know.Ответ:
So your question is:
This can also be written as:
So if we cross multiply, we will get