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campbell387
23.08.2019 •
Mathematics
Find the equation of a line that contains the points (−5,2) and (4,6). write the equation in slope-intercept form.
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Ответ:
y=(4/9)x+(38/9)
Step-by-step explanation:
let (-5,2)=(x1,y1)
(4,6)=(x2,y2)
now
using two point form
y-y1=((y2-y1)/(x2-x1))(x-x1)
or, y-2= ((6-2)/(4-(-5)))(x-(-5))
or,y-2 =4/9 (x+5)
or,9(y-2)=4(x+5)
or,9y-18=4x+20
or,9y= 4x+38
y= (4/9)x+38/9[y=mX+c]
where
m=4/9
c=38/9
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Ответ:
this doesn’t make sense
Step-by-step explanation:
im confused