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saykblahwah309
24.04.2021 •
Mathematics
Find the equation of the axis of symmetry and the coordinates of the vertex of the graph of the function y = 4x^2-8x-3
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Ответ:
x = 1 and vertex = (1, - 7 )
Step-by-step explanation:
Given a quadratic function in standard form
y = ax² + bx + c ( a ≠ 0 )
The the equation of the axis of symmetry which is also the x- coordinate of the vertex is
x = -![\frac{b}{2a}](/tpl/images/2312/0284/306c0.png)
y = 4x² - 8x - 3 ← is in standard form
with a = 4, b = - 8 , then
x = -
= 1
That is equation of axis of symmetry is x = 1
Substitute x = 1 into the function for y- coordinate of vertex
y = 4(1)² - 8(1) - 3 = 4 - 8 - 3 = - 7
vertex = (1, - 7 )
Ответ:
neither
Step-by-step explanation: