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suttonfae336
06.10.2021 •
Mathematics
Find the equation of the line that is perpendicular to the line y = 2/3 x + 3 and goes through the point (0, 8).
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Ответ:
-3/2x + 8
Step-by-step explanation:
To find the slope of the perpendicular line, you take the negative reciprocal first.
2/3 -> -3/2
So far, we have y = -3/2 x + b. (since we use mx + b)
Since you asked for the line to go through (0, 8), we would usually sub in values like below, but since 8 is the y-intercept since x = 0 of the point, and we need the y-intercept, put 8 as the y-intercept.
y = -3/2 x + b
8 = -3/2(0) + b
8 = 0 + b
b = 8
So the equation that passes (0, 8) and is perpendicular to y = 2/3 x + 3 is
-3/2x + 8
Your welcome!
Kayden Kohl
8th Grade
Ответ:
2,500
Step-by-step explanation:
si lo multiplicas