Find the equation of the line that is perpendicular to y = two over three x and contains the point (four,-eight)
PLEASE HELP ME!

When it is perpendicular, the slope is the negative reciprocal so it would equal -3/2x. Plug in the points to the equation so you can find the intercept. -8=-3/2(4)+b
Combine: -8=-6+b
Add 6: -2=b
The equation would be f(x)=-3/2x-2
Hope this helped and sorry if I am wrong!

You use the discriminant (b²-sqr(4ac))/2a and if sqr(4ac) inferior to 0 then use i = sqr(-1)