Find the exact solution of the following equation for 0 degrees <= q <= 360 degrees 4sin^2 q = 3

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Ответ:

cesar2679

27.06.2022

Mathematics

-3 + 4i

Step-by-step explanation:

Absolute Value or the modulus of a Complex Number is the distance between the origin (0,0) and the point (a,b).

That is,

$|a+ib|=\sqrt{(0-a)^2+(0-b)^2}=\sqrt{a^2+b^2}$

Thus,

$|-3 + 4i|=\sqrt{(-3)^2+(4)^2}=\sqrt{9+16}=\sqrt{25}=5$

$|2 + 3i|=\sqrt{(2)^2+(3)^2}=\sqrt{4+9}=\sqrt{13}$

$|7 -2i|=\sqrt{(7)^2+(2)^2}=\sqrt{49+4}=\sqrt{53}$

$|9 + 4i|=\sqrt{(9)^2+(4)^2}=\sqrt{81+16}=\sqrt{97}$

Hence, First option is correct.

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