Find the exact solutions of the given equations, in radians, that lie in the interval [ 0, 2π). cos^2 x - sin^2 x = 0

The equation, in slope-intercept form, of the line that passes through points (2,-2) and (4,1), is: y = 3/2x - 5.

Recall:

Equation of a line in slope-intercept form is: y = mx + b, where, slope = m, and b = y-intercept Equation of a line in point-slope form is: y - b = m(x - a), where, m = slope and (a, b) = a point.Slope (m) =

Given:

(2,-2) and (4,1)

Find the slope:

Write the equation in point-slope form by substituting m = 3/2 and (a, b) = 4, 1) into y - b = m(x - a)

y - 1 = 3/2(x - 4)

Rewrite in slope-intercept form

y - 1 = 3/2(x) - 3/2(4)

y - 1 = 3/2x - 6

y = 3/2x - 6 + 1

y = 3/2x - 5

Therefore, the equation, in slope-intercept form, of the line that passes through points (2,-2) and (4,1), is: y = 3/2x - 5.

Learn more about slope-intercept equation on:

link