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14.05.2021 •
Mathematics
Find the first 5 terms of the arithemitic sequence whose seventh term is 22 and whose eleventh term is 6.
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Ответ:
Step-by-step explanation:
Given that:
The arithemitic sequence whose seventh term is 22 and whose eleventh term is 6.To Find:
The first 5 terms of the arithemitic sequence.We know that:
aₙ = a + (n - 1)dWhere,
aₙ = nth term a = First term n = Number of termsd = Common differenceWe have:
Seventh term = 22
⟶ a + (7 - 1)d = 22
⟶ a + 6d = 22
⟶ a = 22 - 6d
Evelenth term = 6
⟶ a + (11 - 1)d = 6
⟶ a + 10d = 6
Substituting the value of a.
⟶ 22 - 6d + 10d = 6
⟶ 22 + 4d = 6
⟶ 4d = 6 - 22
⟶ 4d = - 16
⟶ d = - 16/4
⟶ d = - 4
In equation (i).
⟶ a = 22 - 6d
Putting the value of d.
⟶ a = 22 - 6(- 4)
⟶ a = 22 + 24
⟶ a = 46
Now we have to find the first 5 terms:
a = 46a + d = 46 + (- 4) = 46 - 4 = 42a + 2d = 46 + 2(- 4) = 46 - 8 = 38a + 3d = 46 + 3(- 4) = 46 - 12 = 34a + 4d = 46 + 4(- 4) = 46 - 16 = 30Hence,
The first 5 terms of the arithemitic sequence are 46, 42, 38, 34 and 30.Ответ:
itsD
Step-by-step explanation: