Find the four arithmetic means between 40 and 10. at first i thought it was 20 and 30, but that's only 2

Inserting four arithmetic means to these numbers will form an arithmetic sequence with first term equal to 40 and sixth term equal to 10. The common difference (d) is calculated by,
                                      d = (a6 - a1) / (6 - 1) 
                                  d = (10 - 40) / (6 - 1) = -6
Thus, the difference between two successive terms in the sequence should be -6. The four arithmetic means are therefore: 34, 28, 22, and 16.

16, -8,4,-2,1
-15,-18, -21.6, -25.92, -31.104,...
625, 125, 25, 5, 1,...
these are the correct ones. sorry it took so long to get an answer