trisngle2565
20.08.2019 •
Mathematics
Find the general solution of the equation:
x dy/dx + y = xe^x
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Ответ:
Step-by-step explanation:
x*(dy/dx) +y = x*(dy/dx) +1*y=x*(dx/dy)+dx/dx*y = (d(xy) /dx)
d(xy) /dx = x^ex<->
d(xy) =xe^x*dx
We integrate both parts with their respective variables.
Integral of d(xy) is xy+c.
Integral of xe^x*dx is equal to xe^x - e^x+c.
We have to integrate by parts:
Integral(x*e^x) = x*e^x - integral((x) 'e^x) = x*e^x - integral(e^x)= x*e^x-e^x.
We have that xy + c = x*e^x - e^x + c1, where c and c1 are non defined real constants.
So we get that xy= x*e^x - e^x + c2, where c2 is a real constant.
Ответ:
sdc
Step-by-step explanation:
sdc