rathaditi4036
07.11.2019 •
Mathematics
Find the half-life of an element which decays by 3.411% each day. hint: use y = ab^t.
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Ответ:
This is about half life of elements with exponential decay.
Half life = 20 years
We are given a decay rate of 3.411% per day.We are given;
y = ab^(t)
Where;
t is the half life
y = a/2 is the amount of substance remaining after decay
a is amount of substance initially
b = 100% - 3.411% = 96.589% = 0.96589
Thus;a/2 = a(0.96589)^(t)
a will cancel out to give;
0.5 = 0.96589^(t)
ln (0.5) = t(ln 0.96589)
t = ln(0.5)/ln(0.96589)
t = 19.968 days
This is approximately 20 days.
Read more at; link
Ответ:
a/2=a(0.96589)^t
0.5=0.96589^t
ln(0.5)=t(ln(0.96589))
t=ln(0.5)/ln(0.96589)
t≈19.97 days (to nearest hundredth of a day)
Ответ:
The equation of the line that passes through (4, -1) and (-2, 3) is 2x +3y - 5 = 0.