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cody4976
26.11.2020 •
Mathematics
Find the HCF of the following by
Prime factorisation,
a) 72,54, 27
b) 24, 16, 36 do this please with full solutions
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Ответ:
here
72, 54, 27 are divisible by 3, to check divisibility by 3 we have to add the digits.
dividing all three digits by 3 we get :
3 x 24 = 72
3 x 18 = 54
3 x 9 = 27
now we have 24, 18, 9
check divisibility by 2, but no, it is not possible. 2 is not divisible by 5 so we take 3, yes three is divisible
24, 18, 9
3 x 8 = 24
3 x 6 = 18
3 x 3 = 9
so now we have 8,6,3
this is neither divisible by 2 or 3 so now we multiply 3 x 3
= 9
second answer is 4
Ответ:
positive line
Step-by-step explanation: