Mathematics: Find the illegal values of b in the fraction

Find the illegal values of b in the fraction

wiredq2049

10.03.2022

$b=4\text { or }b=-2$

Step-by-step explanation:

We have been given a rational expression: $\frac{2b^2+3b-10}{b^2-2b-8}$ and we are asked to find the illegal values of b.

Illegal values of b will be those values, which will make our denominator 0.

To solve for illegal or excluded values of b, let us set our denominator equal to 0.

b^2-2b-8=0

We will factor out our equation by splitting the middle term.

b^2-4b+2b-8=0

b(b-4)+2(b-4)=0

(b-4)(b+2)=0

$b-4=0\text { or }b+2=0$

$b=4\text { or }b=-2$

Therefore, $b=4\text { or }b=-2$ are illegal values of b in the given fraction.

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gshreya2005

19.07.2022

3 + 0 = 3

Step-by-step explanation:

Ty! :)

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