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yagalneedshelp8338
16.06.2020 •
Mathematics
Find the inverse of the function y = x^2 + 12x
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Ответ:
y=x\\
x=y^{2} + 12y\\
y^{2} + 12y -x = 0\\
Delta = (12^{2}) - 4.1.(-x) = 144 +4X = 36.(4+x)
\sqrt{Delta} = 6 . \sqrt{(4+x)} \\
y' = \frac{-12 + 6.(\sqrt{(4+x)}}{2} = -6 + 3.\sqrt{(4+x)}\\
y" = -6 - 3.\sqrt{(4+x)}
y' = 3.\sqrt{(4+x)} - 6\\
y''= -3.\sqrt{(4+x)} - 6\\
Ответ:
slope: (y2-y1)/(x2-x1). So (12-7)/(-39-26). Simplify that and you get 5/-65, which, simplified, is 1/-13.