Find the least common multiple of x2 - 4x – 5 and x2 – 3x – 10.

1 (x + 1)(x - 2)(x - 5)

2 (x - 1)(x - 5)(x - 2)

3 (x + 1)(x - 5)(x + 2)

4 (x - 5)(x+ 2)(x - 1)

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Ответ:

alwaysneedhelp84

24.12.2021

Mathematics

Answer : x = 20

Explanation :
3x + 2x +20 + 4x - 20 = 180

(3+2+4=9)

9x + 20 - 20
The 20s cancel each other out because one is positive and the other is negative

9x = 180

9x/9 = 180/9

X = 180 divided by 9

X = 20

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Find the least common multiple of x2 - 4x – 5 and x2 – 3x – 10.1 (x + 1)(x - 2)(x - 5)2 (x - 1)(x - 5)(x - 2)3 (x + 1)(x - 5)(x + 2)4 (x - 5)(x+ 2)(x - 1)