find the length of the rectangle whose vertices are given.a(2, 1), b(5, 4), c(0, 3), d(3, 6)

 Distance between A and B 
= Distance between C and D 
= sqrt((4 - 1)^2 + (5 - 2)^2) 
= sqrt(3^2 + 3^2) 
= sqrt(2 * 3^2) 
= sqrt(3^2) * sqrt(2) 
= 3sqrt(2) 

Distance between B and C 
= Distance between A and D 
= sqrt((4 - 3)^2 + (5 - 0)^2) 
= sqrt(1^2 + 5^2) 
= sqrt(26) 

Since sqrt(26) is more than 3sqrt(2), the length must be sqrt(26).

they all equal the same. What are you studying right now?

Step-by-step explanation:

7(4x-2)= 14

28x-14=14

28x-14=14

28x=28

x=1

28x-14=14

28x=28

x=1

2(14x-7)=2(7)

28x-14=14

28x=28

x=1

25x+3x-14=7+7

28x-14=14

28x=28

x=1