andrew5632
21.05.2021 •
Mathematics
Find the length of the side C in the triangle ABC where a=4.7 b=10.21 and ACB=105.3
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Ответ:
9514 1404 393
(d) 12.3
Step-by-step explanation:
From the Law of Cosines, you can solve for c:
c = √(a² +b² -2ab·cos(C)) = √(22.09 +104.2441 -95.974cos(105.3°))
c ≈ √151.659 ≈ 12.31499
Side c is about 12.3 units long.
Ответ:
b
10
Step-by-step explanation:
153>63+9b
90>9b
10>b